Python Lists: Find an Item and Its Position

A contact list needs the position of a particular name.

What You Need to Understand

Searching with an explicit loop can return both the value and its position. enumerate() keeps the index aligned with each element.

When to Use It

A contact list needs the position of a particular name.

Step-by-Step Python Example

contacts = ["Maya", "Avi", "Noa"]
target = "Noa"
found_index = None
for position, contact in enumerate(contacts):
    if contact == target:
        found_index = position
        break
print(found_index)

How the Example Works

The loop stops when it finds Noa and returns its zero-based index, 2.

Example Output

2
[0, 2]

A Second Example

Compare this smaller variation with the main example, then experiment with your own values.

status = ["ok", "retry", "ok"]
print([index for index, value in enumerate(status) if value == "ok"])

Important Behavior and Edge Cases

Using None for a missing position is safer than accidentally treating index 0 as false. A list may contain duplicates, so define whether you want the first or all matches.

Try It Yourself

Find every position of a repeated status instead of only its first occurrence.

Common Beginner Mistakes

• Using None for a missing position is safer than accidentally treating index 0 as false. A list may contain duplicates, so define whether you want the first or all matches.
• Overlooking how an iterable is consumed, how element positions are chosen, or whether a function creates a new list.

Key Takeaways

• Searching with an explicit loop can return both the value and its position.
• The loop stops when it finds Noa and returns its zero-based index, 2.
• Using None for a missing position is safer than accidentally treating index 0 as false.